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Heather Watson loses to Tsvetana Pironkova at Australian Open

British number one Heather Watson loses in straight sets to Tsvetana Pironkova in the Australian Open first round.

A below-par Heather Watson has been defeated by Tsvetana Pironkova in the Australian Open first round.

Heather Watson in action on day two of the Australian Open on January 20, 2015© Getty Images

After winning in Hobart last week, Watson came into the first Grand Slam of the year in top form but the British number one, who needed treatment during the match, was easily defeated 6-4 6-0 by the world number 52.

Watson got off to the worst possible start against the Bulgarian as she lost her opening service game, but she looked threatening on her opponent's serve and promptly broke back to level at 2-2.

However, the 22-year-old was performing below her best and after falling a double break behind, the trainer was called and provided Watson with smelling salts.

Tsvetana Pironkova in action on day two of the Australian Open on January 20, 2015© Getty Images

They initially worked as Watson hauled her way back to 5-4, but after Pironkova served out the set she immediately went a break ahead in the second set.

Watson fought on valiantly but after Pironkova swept into a 4-0 advantage, there was only going to be one winner as the Guernsey hitter bowed out at the first stage for the second year in a row.

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Britain's Heather Watson celebrates after winning her women's singles first round match against Croatia's Ajla Tomljanovic on day two of the 2014 Wimbledon Championships at The All England Tennis Club in Wimbledon, southwest London, on June 24, 2014
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